Evaluate the combination:
21C6
A unique order or arrangement
nCr = | n! |
r!(n - r)! |
where n is the number of items
r is the unique arrangements.
21C6 2 | 21! |
6!(21 - 6)! |
n! = n * (n - 1) * (n - 2) * .... * 2 * 1
n! = 21!
21! = 21 x 20 x 19 x 18 x 17 x 16 x 15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
21! = 51,090,942,171,709,440,000
(n - r)! = (21 - 6)!
(21 - 6)! = 15!
15! = 15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
15! = 1,307,674,368,000
r! = 6!
6! = 6 x 5 x 4 x 3 x 2 x 1
6! = 720
21C6 = | 51,090,942,171,709,440,000 |
720 x 1,307,674,368,000 |
21C6 = | 51,090,942,171,709,440,000 |
941,525,544,960,000 |
21C6 = 54,264
21C6 = 54,264
Free Permutations and Combinations Calculator - Calculates the following:
Number of permutation(s) of n items arranged in r ways = nPr
Number of combination(s) of n items arranged in r unique ways = nCr including subsets of sets
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